STUDY/Algorithm
[프로그래머스] LEVEL2 올바른 괄호, python3
sinawi95
2020. 1. 7. 09:06
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def solution(s):
answer=False
if len(s)%2 ==1:
return False
left=0
right=0
for cha in s:
if cha=='(':
left+=1
elif cha==')':
right+=1
if left <right:
break
if left==right:
answer=True
return answer
